NCP1255
40.0
20.0
N1 (Vout + Vf)
off−time
0
−20.0
−40.0
−N2Vbulk
on−time
464u
472u
480u
time in seconds
488u
496u
Figure 5. The signal obtained on the auxiliary winding swings negative during the on−time.
Let’s assume we need to reduce the peak current from 2.5 A at low line, to 2 A at high line. This corresponds to a 20%
reduction or a set point voltage of 640 mV. To reach this level, then the negative voltage developed on the OPP pin must reach:
VOPP + 640 m * 800 m + −160 mV
(eq. 6)
RoppU
This point will
be adjusted to
reduce the ref
at hi line to the
desired level.
Vcc
aux
Vdd
swings to:
Vout during toff
−NVin during ton
from FB
reset
OPP
Iopp
RoppL
K1 SUM2
ref
CS
K2
0.8 V
±5%
ref = 0.8 V + VOPP
(VOPP is negative)
Figure 6. The OPP circuitry affects the maximum peak current set point by
summing a negative voltage to the internal voltage reference.
Let us assume that we have the following converter
characteristics:
Vout = 19 V
Vin = 85 to 265 V rms
N1 = Np:Ns = 1:0.25
N2 = Np:Naux = 1:0.18
Given the turns ratio between the primary and the
auxiliary windings, the on−time voltage at high line
(265 Vac) on the auxiliary winding swings down to:
Vaux + −N2Vin,max + −0.18 375 + −67.5 V (eq. 7)
To obtain a level as imposed by Equation 6, we need to
install a divider featuring the following ratio:
Div
+
0.16
67.5
[
2.4
m
(eq. 8)
If we arbitrarily fix the pull−down resistor ROPPL to 1 kW,
then the upper resistor can be obtained by:
ROPPU
+
67.5 * 0.16
0.16ń1 k
[
421
kW
(eq. 9)
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